2x 2 6x 1 0.

x2-6x-7=0 Two solutions were found : x = 7 x = -1 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-6x-7 The first term is, x2 its ... 2x2-6x-7=0 Two solutions were found : x = (6-√92)/4= (3-√ 23 )/2= -0.898 x = (6+√92)/4= (3+√ 23 )/2= 3.898 Step by step solution : Step 1 :Equation at the end ...

Solution, 3a. Solve Quadratic equation by completing square method. 2 x 2 + 6 x + 1 = 0. Subtract 1 from both sides of the equation. 2 x 2 + 6 x = − 1. Divide each term in 2 x 2 + 6 x = − 1 by 2 and simplify. x 2 + 3 x = − 1 2. To create a trinomial square on the left side of the equation, find a value that is equal to the squ....

x2-6x-91=0 Two solutions were found : x = 13 x = -7 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-6x-91 The first term is, x2 its ... -x2-6x-91=0 Two solutions were found : x = (6-√-328)/-2=3+i√ 82 = -3.0000-9.0554i x = (6+√-328)/-2=3-i√ 82 = -3.0000+9.0554i Step by step solution : Step 1 ...3x2-6x+1=0 Two solutions were found : x = (6-√24)/6=1-1/3√ 6 = 0.184 x = (6+√24)/6=1+1/3√ 6 = 1.816 Step by step solution : Step 1 :Equation at the end of step 1 : (3x2 - 6x) + 1 = 0 Step ... 13x2-6x+1=0 Two solutions were found : x = (6-√-16)/26= (3-2i)/13= 0.2308-0.1538i x = (6+√-16)/26= (3+2i)/13= 0.2308+0.1538i Step by step ...x^2-6x-160. 2x{(x-6)}^{2} 3x^2-10x+8. Kembali ke atas. Bahasa Indonesia Tentang Math Solver; Soal-Soal yang Sering Ditemukan ...Algebra. Solve by Factoring 6x^2+x-2=0. 6x2 + x − 2 = 0 6 x 2 + x - 2 = 0. Factor by grouping. Tap for more steps... (2x−1)(3x+2) = 0 ( 2 x - 1) ( 3 x + 2) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. 2x−1 = 0 2 x - 1 = 0. 3x+2 = 0 3 x + 2 = 0.

Function Line f(x) = 2x2 6x − y + 1 = 0 Find the slope of the tangent line to the graph of the function at the given point. This problem has been solved! ... = 2x 2. 6x − y + 1 = 0. Find the slope of the tangent line to the graph of the function at the given point. g(x) = 4: x + 7, (-5, 3) 5: Expert Answer.Expert-Verified Answer question 28 people found it helpful carlosego report flag outlined To solve this problem you must apply the proccedure shown below: 1. You have the following quadratic equation given in the exercise above: 2x²−6x+1=0 2. The quadratic equation is: x= [-b±√ (b²-4ac)]/2a Where: a=2 b=-6 c=1 3.

6x2-6x=0 Two solutions were found : x = 1 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 6x = 0 Step 2 : Step 3 :Pulling out like terms : 3.1 ... 6x2-36x=0 Two solutions were found : x = 6 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 36x = 0 Step 2 : Step 3 :Pulling out ...Free Polynomial Standard Form Calculator - Reorder the polynomial function in standard form step-by-step.

x^2-6x-160. 2x{(x-6)}^{2} 3x^2-10x+8. Kembali ke atas. Bahasa Indonesia Tentang Math Solver; Soal-Soal yang Sering Ditemukan ...Solve Using the Quadratic Formula 6x^2-x-2=0. 6x2 − x − 2 = 0 6 x 2 - x - 2 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 6 a = 6, b = −1 b = - 1, and c = −2 c = - 2 into the quadratic formula and solve for x x. 1±√(−1)2 −4 ⋅(6⋅−2) 2⋅6 1 ... 2.1 Factoring 5x2+6x+1. The first term is, 5x2 its coefficient is 5 . The middle term is, +6x its coefficient is 6 . The last term, "the constant", is +1. Step-1 : Multiply the coefficient of the first term by the constant 5 • 1 = 5. Step-2 : Find two factors of 5 whose sum equals the coefficient of the middle term, which is 6 . Example 9.2.3. Solve by completing the square: x2 + 14x + 46 = 0. Solution: Step 1: Add or subtract the constant term to obtain the equation in the form x2 + bx = c. In this example, subtract 46 to move it to the right side of the equation. Step 2: Use (b 2)2 to determine the value that completes the square. Here b = 14:Rearrange into the form: (x−4)2 +(y−3)2 = 22 to identify the centre (4,3) and radius 2 ... Find the equations of the circles that have centre (0,0) and touch the circle x2 + y2 − 8x − 6y + 24 = 0. This does not need calculus, just a theorem from euclidean geometry. The given circle has centre (4,3) and radius 1 unit.


Tres enralla

ALJABAR Kelas 9 SMP. PERSAMAAN KUADRAT. Akar Persamaan Kuadrat. Akar-akar persamaan 2x^2 - 6x + 1 = 0 adalam m dan n. Persamaan kuadrat yang akar-akarnya m/n dan n/m adalah. Akar Persamaan Kuadrat.

Sign in. Free equations calculator - solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps. Type in any equation to get the solution, ….

factor quadratic x^2-7x+12; expand polynomial (x-3)(x^3+5x-2) GCD of x^4+2x^3-9x^2+46x-16 with x^4-8x^3+25x^2-46x+16; quotient of x^3-8x^2+17x-6 with x-3; remainder of x^3-2x^2+5x-7 divided by x-3; roots of x^2-3x+2; View more examples; Access instant learning tools. Get immediate feedback and guidance with step-by-step solutions and Wolfram ... Solve for x: y=-2x^2-6x+1 2x^2+6x+y-1=0 Use the quadratic formula with a=2, b=6, c=y-1 x=(-6 +-sqrt ((6)^2-4 (2)(y-1)))/4 This will give real numbers for x if 36-8y+8 >= 0 44>=8y y <= 11/2 The range is all reals less than or equal to 11/2. The interval (-oo, 5/2) Algebra . ScienceQuadratic Equations in Vertex Form have a general form: #color(red)(y=f(x)=a(x-h)^2+k#, where #color(red)((h,k)# is the #color(blue)("Vertex"# Let us consider a quadratic equation in Vertex Form:Functions. A function basically relates an input to an output, there’s an input, a relationship and an output. For every input... Read More. Save to Notebook! Sign in. Free functions symmetry calculator - find whether the function is symmetric about x …Step 2 : Trying to factor by splitting the middle term. 2.1 Factoring 9x2-6x+1. The first term is, 9x2 its coefficient is 9 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is +1. Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9. Step-2 : Find two factors of 9 whose sum equals the ...

kx 2 + 2x + 1 = 0. It’s of the form of ax 2 + bx + c = 0. Where, a =k, b = 2, c = 1. For the given quadratic equation to have real roots D = b 2 – 4ac > 0. D = (2) 2 – 4(1)(k) > 0. ⇒ 4 – 4k > 0. ⇒ 4k < 4. ⇒ k < 1. The value of k should be lesser than 1 to have real and distinct roots. (ii) kx 2 + 6x + 1 = 0. Solution: Given, kx 2 ...Misalnya, Anda harus memfaktorkan 2x 2 − 6x − 18x. Faktor persekutuan terbesar dari persamaan ini adalah 2x. Memiliki 2x sebagai faktor persekutuan terbesar, kita dapat memfaktorkan persamaan ini sebagai: $$2x(x-3-9)$$ Kalkulator faktorisasi prima kami juga berurusan dengan pemfaktoran kuadrat.x2+6x+5=0 Two solutions were found : x = -1 x = -5 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+6x+5 The first term is, x2 its ... 2x2+6x+5=0 Two solutions were found : x = (-6-√-4)/4= (-3-i)/2= -1.5000-0.5000i x = (-6+√-4)/4= (-3+i)/2= -1.5000+0.5000i Step by step solution : Step 1 ...Factor 6x^2-x-1. 6x2 − x − 1 6 x 2 - x - 1. For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 6⋅−1 = −6 a ⋅ c = 6 ⋅ - 1 = - 6 and whose sum is b = −1 b = - 1. Tap for more steps... 6x2 + 2x−3x−1 6 x 2 + 2 x - 3 x - 1. Factor out the greatest common ... Equation at the end of step 1 : x 2 - 6x - 1 = 0 Step 2 : Parabola, Finding the Vertex : 2.1 Find the Vertex of y = x 2-6x-1 Parabolas have a highest or a lowest point called the …2*x^2-(6*x-1)=0 . Step by step solution : Step 1 : Equation at the end of step 1 : 2x 2 - (6x - 1) = 0 Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 2x 2-6x+1 The first term is, 2x 2 its coefficient is 2 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is +1

Solve Using the Quadratic Formula x^2+6x-1=0. x2 + 6x − 1 = 0 x 2 + 6 x - 1 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 1 a = 1, b = 6 b = 6, and c = −1 c = - 1 into the quadratic formula and solve for x x. −6±√62 −4⋅ (1⋅−1) 2⋅1 - 6 ± 6 2 ...

Solve Using the Quadratic Formula 2x^2-2x-1=0. 2x2 − 2x − 1 = 0 2 x 2 - 2 x - 1 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 2 a = 2, b = −2 b = - 2, and c = −1 c = - 1 into the quadratic formula and solve for x x. 2±√(−2)2 −4 ⋅(2⋅−1) 2⋅ ...Factor 2x^2+x-1. 2x2 + x − 1 2 x 2 + x - 1. For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 2⋅−1 = −2 a ⋅ c = 2 ⋅ - 1 = - 2 and whose sum is b = 1 b = 1. Tap for more steps... 2x2 − 1x+2x−1 2 x 2 - 1 x + 2 x - 1. Factor out the greatest common factor ...Free Complete the Square calculator - complete the square for quadratic functions step-by-step. 2x2-6x-16=0 Two solutions were found : x = (3-√41)/2=-1.702 x = (3+√41)/2= 4.702 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 6x) - 16 = 0 Step 2 : Step 3 ... 3x2-6x-16=0 Two solutions were found : x = (6-√228)/6=1-1/3√ 57 = -1.517 x = (6+√228)/6=1+1/3√ 57 = 3.517 Step by step solution : Step 1 :Equation at ...Two numbers r and s sum up to -3 exactly when the average of the two numbers is \frac{1}{2}*-3 = -\frac{3}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C.solve equation $6x^3 - 25x^2 + 2x + 8 = 0$ example 4: ex 4: find polynomial roots $2x^3-x^2-x-3$ example 5: ex 5: find roots $2x^5-x^4-14x^3-6x^2+24x+40$ ... Example 04: Solve the equation $ 2x^3 - 4x^2 - 3x + 6 = 0 $. Step 1: Guess one root. The good candidates for solutions are factors of the last coefficient in the equation. In this example ...4x2+6x+2=0 Two solutions were found : x = -1 x = -1/2 = -0.500 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 + 6x) + 2 = 0 Step 2 : Step 3 :Pulling out like ... How do you solve the equation 4x2 = 20x − 25 by completing the square? 25 Explanation: given, 4x2 = 20x−25 ⇒4x2−20x+25 = 0 ⇒(2x)2−2⋅2x⋅5 +(5)2 ...Jan 21, 2017 · Explanation: Given -. 2x2 − 6x +1 = 0. 2x2 − 6x = −1. 2x2 2 − 6x 2 = −1 2. x2 −3x = −1 2. x2 −3x + 9 4 = −1 2 + 9 4. (x − 3 2)2 = −2 +9 4 = 7 4. (x − 3 2) = ± √ 7 4. In girl’s clothing, a size 6x is a little bit longer and a bit larger in width than a size 6. It is comparable to a size 6 1/2, fitting somewhere between a size 6 and a size 7. In addition to allowing the clothes to fit the girl better, imp...


The language of composition 3rd edition answer key pdf

Free functions range calculator - find functions range step-by-step

Precalculus. Factor 2x^2+6x+1. 2x2 + 6x + 1 2 x 2 + 6 x + 1. 2x2 + 6x+1 2 x 2 + 6 x + 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Click here👆to get an answer to your question ️ For what value of a, the roots of the equation 2x^2 + 6x + a = 0 , satisfy the conditions (alphabeta) + (betaalpha) < 2 (where beta,alpha are the roots of equation).x2-6x-1=0 Two solutions were found : x = (6-√40)/2=3-√ 10 = -0.162 x = (6+√40)/2=3+√ 10 = 6.162 Step by step solution : Step 1 :Trying to factor by splitting the middle term ... 2x2-6x-1=0 Two solutions were found : x = (6-√44)/4= (3-√ 11 )/2= -0.158 x = (6+√44)/4= (3+√ 11 )/2= 3.158 Step by step solution : Step 1 :Equation at ...Click here👆to get an answer to your question ️ For what value of a, the roots of the equation 2x^2 + 6x + a = 0 , satisfy the conditions (alphabeta) + (betaalpha) < 2 (where beta,alpha are the roots of equation).Example 03: Solve equation $ 2x^2 - 10 = 0 $ This is also a quadratic equation that can be solved without using a quadratic formula.. $$ \begin{aligned} 2x^2 - 18 &= 0 \\ 2x^2 &= 18 \\ x^2 &= 9 \\ \end{aligned} $$ The last equation actually has two solutions. The first one is obvious $$ \color{blue}{x_1 = \sqrt{9} = 3} $$ and the second one is Algebra. Solve by Factoring 6x^2+x-2=0. 6x2 + x − 2 = 0 6 x 2 + x - 2 = 0. Factor by grouping. Tap for more steps... (2x−1)(3x+2) = 0 ( 2 x - 1) ( 3 x + 2) = 0. If any individual …Divide \frac{6}{5}, the coefficient of the x term, by 2 to get \frac{3}{5}. Then add the square of \frac{3}{5} to both sides of the equation. This step makes the left hand side of the equation a perfect square.High School Math Solutions - Quadratic Equations Calculator, Part 1. A quadratic equation is a second degree polynomial having the general form ax^2 + bx + c = 0, where a, b, and c... Read More. Save to Notebook! Free quadratic equation calculator - Solve quadratic equations using factoring, complete the square and the quadratic formula step ...Solve Quadratic Equation by Completing The Square. 2.2 Solving x2-6x-1 = 0 by Completing The Square . Add 1 to both side of the equation : x2-6x = 1. Now the clever bit: Take the coefficient of x , which is 6 , divide by two, giving 3 , and finally square it giving 9. Add 9 to both sides of the equation : On the right hand side we have :3.2 Solving 3x2-6x+1 = 0 by Completing The Square . Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2-2x+ (1/3) = 0. Subtract 1/3 from both side of the equation : x2-2x = -1/3. Now the clever bit: Take the coefficient of x , which is 2 , divide by two, giving 1 , and finally square it giving 1.

2.1 Factoring 5x2+6x+1. The first term is, 5x2 its coefficient is 5 . The middle term is, +6x its coefficient is 6 . The last term, "the constant", is +1. Step-1 : Multiply the coefficient of the first term by the constant 5 • 1 = 5. Step-2 : Find two factors of 5 whose sum equals the coefficient of the middle term, which is 6 .Algebra Solve Using the Quadratic Formula 6x^2-x-1=0 6x2 − x − 1 = 0 6 x 2 - x - 1 = 0 Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a Substitute the values a = 6 a = 6, b = −1 b = - 1, and c = −1 c = - 1 into the quadratic formula and solve for x x.10 Contoh soal polinomial dan pembahasannya. Nilai dari 6x 5 + 2x 3 + 4x 2 + 6 untuk x = -1 adalah …. Jika nilai dari 2x 4 + mx 3 – 8x + 3 untuk x = 3 adalah 6 maka m adalah …. Jika f (x) = x 3 + 5x 2 – 3x + 9 dibagi (x – 2) maka hasil baginya adalah …. Jadi hasil bagi = x 2 + 7x = 11 dan sisa = 31. Soal ini jawabannya D. wwwwwwwww Algebra Solve Using the Quadratic Formula 2x^2-6x+1=0 2x2 − 6x + 1 = 0 2 x 2 - 6 x + 1 = 0 Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a Substitute the values a = 2 a = 2, b = −6 b = - 6, and c = 1 c = 1 into the quadratic formula and solve for x x.9x2+6x+1=0 One solution was found : x = -1/3 = -0.333 Step by step solution : Step 1 :Equation at the end of step 1 : (32x2 + 6x) + 1 = 0 Step 2 :Trying to factor by ... x2+6x+10=0 Two solutions were found : x = (-6-√-4)/2=-3-i= -3.0000-1.0000i x = (-6+√-4)/2=-3+i= -3.0000+1.0000i Step by step solution : Step 1 :Trying to factor by ... new jersey snowfall today Solve Using the Quadratic Formula 6x^2-x-2=0. 6x2 − x − 2 = 0 6 x 2 - x - 2 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 6 a = 6, b = −1 b = - 1, and c = −2 c = - 2 into the quadratic formula and solve for x x. 1±√(−1)2 −4 ⋅(6⋅−2) 2⋅6 1 ...Functions. A function basically relates an input to an output, there’s an input, a relationship and an output. For every input... Read More. Save to Notebook! Sign in. Free Functions End Behavior calculator - find function end behavior step-by-step. amazon gazebo sale x2+6x+5=0 Two solutions were found : x = -1 x = -5 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+6x+5 The first term is, x2 its ... 2x2+6x+5=0 Two solutions were found : x = (-6-√-4)/4= (-3-i)/2= -1.5000-0.5000i x = (-6+√-4)/4= (-3+i)/2= -1.5000+0.5000i Step by step solution : Step 1 ... lowe's chandeliers crystal Solve by Completing the Square x^2-6x+5=0. Step 1. Subtract from both sides of the equation. Step 2. To create a trinomial square on the left side of the equation, ... Step 6.2.1. Rewrite as . Step 6.2.2. Pull terms out from under the radical, assuming positive real numbers. Step 6.3. razor mx350 reset button location Aug 17, 2023 · To complete the square when a is greater than 1 or less than 1 but not equal to 0, divide both sides of the equation by a. This is the same as factoring out the value of a from all other terms. As an example let's complete the square for this quadratic equation: 2x2 − 12x + 7 = 0 2 x 2 − 12 x + 7 = 0. a ≠ 1, and a = 2, so divide all terms ... Factor 6x^2-x-1. 6x2 − x − 1 6 x 2 - x - 1. For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 6⋅−1 = −6 a ⋅ c = 6 ⋅ - 1 = - 6 and whose sum is b = −1 b = - 1. Tap for more steps... 6x2 + 2x−3x−1 6 x 2 + 2 x - 3 x - 1. Factor out the greatest common ... joann fabrics hudson ny di sini ada soal diketahui akar-akar persamaan kuadrat 2 x kuadrat min 4 x ditambah 1 sama dengan nol adalah Alfa dan Beta persamaan kuadrat baru yang akar-akarnya alfa beta dan Beta per Alfa adalah untuk mengerjakan ini kita akan gunakan konsep persamaan kuadrat di mana bentuk umumnya yaitu a AX kuadrat + BX + c = 0 di sini kita akan … my man baby brother is finally facing the music Solve by Completing the Square x^2-6x-1=0 | Mathway Algebra Examples Popular Problems Algebra Solve by Completing the Square x^2-6x-1=0 x2 − 6x − 1 = 0 x 2 - 6 x - 1 = 0 Add 1 1 to both sides of the equation. x2 − 6x = 1 x 2 - 6 x = 1Quadratic Equation in Standard Form: ax 2 + bx + c = 0. Quadratic Equations can be factored. Quadratic Formula: x = −b ± √ (b2 − 4ac) 2a. When the Discriminant ( b2−4ac) is: positive, there are 2 real solutions. zero, there is one real solution. negative, there are 2 complex solutions.Solve Solve for x x = 211+3 ≈ 3.158312395 x = 23− 11 ≈ −0.158312395 Steps Using the Quadratic Formula Steps for Completing the Square Steps Using Direct Factoring Method View solution steps Graph Graph Both Sides in 2D Graph in 2D Quiz Quadratic Equation 2x2 −6x−1 = 0 Similar Problems from Web Search 2x2 − 6x − 1 = 0 paracordist diamond knot 2x2+6x+1=0 Two solutions were found : x =(-6-√28)/4=(-3-√ 7 )/2= -2.823 x =(-6+√28)/4=(-3+√ 7 )/2= -0.177 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 + 6x) + 1 = ... lkq inventory locations How do you factor completely x2 − 6x + 8 ? Neh Pandya Apr 29, 2016 For x2 −6x+8 =0 0 = x2−4x−2x+8 0 =x(x−4)−2(x−4) ... x2-6x+1 Final result : x2 - 6x + 1 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-6x+1 The first term is, x2 its coefficient is 1 . ullu web series free watch Similar Problems from Web Search. 1 ≤ f (x)<37 Explanation: First, we find the minimum point the graph reaches by differentiationg and making that equal . f (x) =x2 −6x+10 ... What are the extrema of f (x) = x2 − 6x + 11 on x ∈ [1,6] ? (3,2) is a minimum. (1,6) and (6,11) are maxima. Explanation: Relative extrema occur when f ′(x)= 0 ...Equation at the end of step 1 : (2x 2 - 6x) - 20 = 0 Step 2 : Step 3 : Pulling out like terms : 3.1 Pull out like factors : 2x 2 - 6x - 20 = 2 • (x 2 - 3x - 10) Trying to factor by splitting the middle term 3.2 Factoring x 2 - 3x - 10 The first term is, x 2 its coefficient is 1 . The middle term is, -3x its coefficient is -3 . conan exiles isle of siptah spider location Equation at the end of step 1 : x 2 - 6x - 1 = 0 Step 2 : Parabola, Finding the Vertex : 2.1 Find the Vertex of y = x 2-6x-1 Parabolas have a highest or a lowest point called the …6x2-6x=0 Two solutions were found : x = 1 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 6x = 0 Step 2 : Step 3 :Pulling out like terms : 3.1 ... 6x2-36x=0 Two solutions were found : x = 6 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 36x = 0 Step 2 : Step 3 :Pulling out ...